2aHawaii
General Topics => Political Discussion => Topic started by: punaperson on March 09, 2016, 07:49:10 AM
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Although Hawaii and Idaho are similar in population, ranked 40th and 39th respectively, there are some differences to be noted in yesterday's Republican primaries/caucuses.
Republican Primary Election Hawaii vs. Idaho: Similarities and Disparities
Population (2015 est.):
Hawaii 1,431,603 (rank: 40th)
Idaho 1,654,930 (rank 39th) (+15.6%)
Republican convention delegates:
Hawaii 19
Idaho 32 (+68%)
Voters in Republican primary/caucus March 8 2016:
Hawaii 13,377
Idaho 222,213 (+1,516%)
Percent votes for top two candidates:
Hawaii
Trump 42.44% (+30%)
Cruz 32.74 %
Idaho
Cruz 45.4% (+62%)
Trump 28.1%
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WTF, why are the delegates so different in number?
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Because 60-70% of Hawaii doesn't vote, and the majority that do are democrats, which is why they get more delegates.
13000 is only .90% of the total population of Hawaii.
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WTF, why are the delegates so different in number?
Just to reiterate what Q wrote, in Idaho, a state of approximately the same total population as Hawaii, 15 (fifteen) TIMES as many Republicans cared enough to vote in the primary. That many involved people should (according to "one person, one vote") be given more weight toward the ultimate selection of a candidate than the "ainokea" state. If anything, the disparity in delegates should be even (far) greater in Idaho's favor. Hawaii is getting one delegate/convention vote for every 704 Hawaii voters, while Idaho is getting one delegate/convention vote for every 6,944 Idaho voters. So each Hawaii voter has 10 times the weight as each Idaho voter in determining the party candidate. Here is where that non-proportional weighting difference matters: in essence Trump (Hawaii) got 10 times the proportional delegates as did Cruz (Idaho).