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Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½ (Read 7490 times)

Rocky

Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« on: April 29, 2017, 03:41:45 PM »
This is getting pretty anal but a there's a whole  $#1tl0ad   of info here  :D  ;D   :-\  :-[    ???   >:(  :crazy: :crazy: :crazy: :crazy: :crazy:

http://www.jbmballistics.com/ballistics/calculators/calculators.shtml
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“I ask you to judge me by the enemies I have made.”
                                                           Franklin D. Roosevelt

FBI

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #1 on: April 29, 2017, 04:55:17 PM »
Furthest I got in university was
Linear Algebra. I do have a degree
Few Americans earn.  It is boring
as hell.
I have written Diff EQ algorithms
for my previous employers.
But the mess you print out
means nothing without defining
your variables.
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ren

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #2 on: April 29, 2017, 05:06:43 PM »
Quote from: FBI on April 29, 2017, 04:55:17 PM
Furthest I got in university was
Linear Algebra. I do have a degree
Few Americans earn.  It is boring
as hell.
I have written Diff EQ algorithms
for my previous employers.
But the mess you print out
means nothing without defining
your variables.

Logged
Deeds Not Words

Flapp_Jackson

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #3 on: April 29, 2017, 05:10:06 PM »
Quote from: FBI on April 29, 2017, 04:55:17 PM
Furthest I got in university was
Linear Algebra. I do have a degree
Few Americans earn.  It is boring
as hell.
I have written Diff EQ algorithms
for my previous employers.
But the mess you print out
means nothing without defining
your variables.

Curious.... is that Bachelor's degree in "Anarchy" a BA or BS?

I'm leaning toward it being BS....
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The reasonable man adapts himself to the world;
the unreasonable one persists in trying to adapt the world to himself.
Therefore, all progress depends on the unreasonable man.
-- George Bernard Shaw

mrgaf

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #4 on: April 29, 2017, 05:21:36 PM »
Quote from: Flapp_Jackson on April 29, 2017, 05:10:06 PM
Curious.... is that Bachelor's degree in "Anarchy" a BA or BS?

I'm leaning toward it being BS....

Dang hoss! You're pretty brutal.... who cares if it's BS, BA, OU812.... it's funny as shit! 😄
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To argue with a person who has renounced the use of reason is like administering medicine to the dead.  Thomas Paine.

No man can get rich in politics unless he is a crook.  It cannot be done. Harry Truman

Only good liberal is one taking a dirt nap.

Rocky

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #5 on: April 30, 2017, 08:44:51 AM »
Quote from: FBI on April 29, 2017, 04:55:17 PM
Furthest I got in university was
Linear Algebra. I do have a degree
Few Americans earn.  It is boring
as hell.
I have written Diff EQ algorithms
for my previous employers.
But the mess you print out
means nothing without defining
your variables.
To use the equation, you must fill in the variables as they are ever changing. :geekdanc:
Type, length, weight of bullet, barrel twist, length, scope angle, line of sight, humidity, temperature, altitude other atmospheric conditions, gravity, Transverse Moment of Inertia ....  :crazy: 
   Never mind.
 This algorithm is based on the McDrag work done by Robert McCoy.
You may find what you seek there.
« Last Edit: April 30, 2017, 08:58:08 AM by Rocky »
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“I ask you to judge me by the enemies I have made.”
                                                           Franklin D. Roosevelt

mrgaf

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #6 on: April 30, 2017, 08:58:38 AM »
Quote from: Rocky on April 30, 2017, 08:44:51 AM
To use the equation, you must fill in the variables as they are ever changing. :geekdanc:
Type, length, weight of bullet, barrel twist, length, humidity, temperature, altitude other atmospheric conditions....  :crazy: 
   Never mind.
Told you it had something to do with anal. :rofl: :rofl:

Now what would the equation be to measure not only the velocity but foot pounds of pressure of a real good bit of flatulance.  :crazy:
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To argue with a person who has renounced the use of reason is like administering medicine to the dead.  Thomas Paine.

No man can get rich in politics unless he is a crook.  It cannot be done. Harry Truman

Only good liberal is one taking a dirt nap.

Rocky

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #7 on: April 30, 2017, 10:23:55 AM »
Quote from: mrgaf on April 30, 2017, 08:58:38 AM
Now what would the equation be to measure not only the velocity but foot pounds of pressure of a real good bit of flatulance.  :crazy:
      Fart (F)  velocity could easily be measured via Handheld Anemometer

    Assuming F had a weight of 300 gr and traveled at 32.2 ft/sec2
F = w/g = (300gr)/[7000 gr/lb 32.2 ft/sec2] = 0.00133 lb sec2/ft
Then potential energy is...
PE = [0.00133 lb sec2/ft] * [32.2 ft/sec2] * [6 ft] = 0.26 ft-lbs
Angle of F would probably alter above calc and necessitate the use of the Runge Kutta method (possibly RK4 ?)  for corrections.

 :geekdanc: 

     Is this correct FBI  ?
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“I ask you to judge me by the enemies I have made.”
                                                           Franklin D. Roosevelt

rklapp

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #8 on: April 30, 2017, 01:53:31 PM »
All you have to do is integrate the derivative for the area under the curve as x approaches infinity. Simple...
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Yahh! Freedom and justice shall always prevail over tyranny, Babysitter Girl!
https://ronsreloading.wordpress.com/

Flapp_Jackson

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #9 on: April 30, 2017, 01:55:39 PM »
Quote from: rklapp on April 30, 2017, 01:53:31 PM
All you have to do is integrate the derivative for the area under the curve as x approaches infinity. Simple...

There's no "x" in the formula, so infinity for x isn't happening!   :geekdanc:
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The reasonable man adapts himself to the world;
the unreasonable one persists in trying to adapt the world to himself.
Therefore, all progress depends on the unreasonable man.
-- George Bernard Shaw

rklapp

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #10 on: April 30, 2017, 07:44:27 PM »
Quote from: Flapp_Jackson on April 30, 2017, 01:55:39 PM
There's no "x" in the formula, so infinity for x isn't happening!   :geekdanc:
It's not a real equation if there's no x variable. Sheesh...
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Yahh! Freedom and justice shall always prevail over tyranny, Babysitter Girl!
https://ronsreloading.wordpress.com/

RSN172

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #11 on: May 01, 2017, 08:45:23 AM »
I not ashamed to say all this logarithm analytical stuff is way over my head.  Mine is much simpler.  Aim+Shoot+Desired results=Success.
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Happily living in Puna

rklapp

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #12 on: May 01, 2017, 09:24:17 AM »
Quote from: RSN172 on May 01, 2017, 08:45:23 AM
I not ashamed to say all this logarithm analytical stuff is way over my head.  Mine is much simpler.  Aim+Shoot+Desired results=Success.
You forgot the exponential in the "Desired results" variable.
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Yahh! Freedom and justice shall always prevail over tyranny, Babysitter Girl!
https://ronsreloading.wordpress.com/

FBI

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #13 on: May 01, 2017, 11:36:01 AM »
Quote from: Flapp_Jackson on April 29, 2017, 05:10:06 PM
Curious.... is that Bachelor's degree in "Anarchy" a BA or BS?

I'm leaning toward it being BS....

It is BS!
Add in some Berkley physics Graduate
credit also.
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Flapp_Jackson

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #14 on: May 01, 2017, 11:40:02 AM »
Quote from: FBI on May 01, 2017, 11:36:01 AM
It is BS!
Add in some Berkley physics Graduate
credit also.

 :thumbsup:
 :rofl: :rofl: :rofl:
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The reasonable man adapts himself to the world;
the unreasonable one persists in trying to adapt the world to himself.
Therefore, all progress depends on the unreasonable man.
-- George Bernard Shaw

RSN172

Re: Tm=d √30m/s d3 ∫(1+∫2) ƒv½ = √30m d2/s L(d2+L2) ƒv½
« Reply #15 on: May 01, 2017, 01:45:36 PM »
Quote from: rklapp on May 01, 2017, 09:24:17 AM
You forgot the exponential in the "Desired results" variable.
Told you it is over my head.  Main thing I know how to count money.
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Happily living in Puna
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